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5k^2+33k-56=0
a = 5; b = 33; c = -56;
Δ = b2-4ac
Δ = 332-4·5·(-56)
Δ = 2209
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{2209}=47$$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(33)-47}{2*5}=\frac{-80}{10} =-8 $$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(33)+47}{2*5}=\frac{14}{10} =1+2/5 $
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